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--- ecen_240_assignments [2016/02/28 00:10]
petersen
+++ ecen_240_assignments [2016/09/07 09:18] (current)
wilde [MT240.NR.0]
@@ Line 32: / Line 32: @@
 | Ch 10     | [[ecen_240_assignments#MT240.NR.10|MT240.NR.10]]         | Sinusoidal Steady-State Power Calc|                                                                                                                             |
 | :::       | [[ecen_240_assignments#MT240.NR.10.4.1|MT240.NR.10.4.1]] | Complex Power                     |     [[matlab_guide#Annotation| Text]]                                                                                       |
+| :::       | [[ecen_240_assignments#MT240.NR.10.4.2|MT240.NR.10.4.2]] | Complex Power                     |     Review                                                                                       |
 | Ch 12     | [[ecen_240_assignments#MT240.NR.12|MT240.NR.12]]         | Intro to L. Transform             |                                                                                                                             |
 | Ch 13     | [[ecen_240_assignments#MT240.NR.13|MT240.NR.13]]         | L Transform in Circuit Analysis   |                                                                                                                             |
@@ Line 45: / Line 46: @@
 Read and follow along with the document to get an introduction to MATLAB. \\
-{{:240matlab:ch0:matlab_intro.docx|}} \\
+{{:240matlab:ch0:matlab_intro.pdf|}} \\
 After completing the document, make sure that you feel comfortable with the following MATLAB topics:
@@ Line 212: / Line 213: @@
 ===== Z-Circuit Analysis with Mesh Current Method =====
 ==== MT240.NR.9.9.1 ====
+== Document ==
-<file>
+{{:240matlab:ch9:mt240_9_9_1_mesh_current_method.pdf|}}
- MT240_9_9_1 Mesh_Current Method
- Objective: Design a circuit using capacitors and resistors that cause
- Vout to be 180 degrees out of phase with Vin.
- Background: Oscillators can be constructed from op-amps and an RC network.
- The basic theory is to create a 180 degree phase shift between Vin and
- Vout. This will cuase the op-amp to continuously oscillate in attempt to
- make both inputs the same voltage level (virtual short).
- Exercise: Refer to the provided image for this problem.
- You want to design a circuit that will oscillate at 40e3 Hz. You only
- have one resistor value (R = 1e3 ohms), but you have the various
- capacitors available (C = 1e-9:1e-10:20e-9). You decide to write a
- program to calculate the angle of Vout in reference to Vin as a function of
- Capacitance. To simplify calculations, you decide that every resistor
- must have the same value and every capacitor must have the same value.
- Also, since you are only interested in the phase shift of Vout, assume
- Vin to have a value of 1AC
-                 %Variables
-                 C = 1e-9:1e-10:20e-9;
-                 R = 1e3;
-                 w = 2*pi*40000;
-                 ZC = 1./(1j*w*C);
-                 Vin = 1;
-                 ic = zeros(1,length(ZC));  allocate space
-          a) Label the currents in each mesh from left to right ia,ib, and ic.
-              Use mesh current method to write a system of equations.
-                 System of Equations
-                 Vin = ia(...) + ib(...) + ic(...)
-   = ia(...) + ib(...) + ic(...)
-   = ia(...) + ib(...) + ic(...)
-              Put the system of equations into matrix form.
-                                   Matrices
-                              Impedances            Currents     A
-                    | (...)    (...)    (...)    | * | ia | = | Vin |
-                    | (...)    (...)    (...)    | * | ib | = |  0  |
-                    | (...)    (...)    (...)    | * | ic | = |  0  |
-           b) Solve for ic for every capacitor value. Remember that all
-              three capacitors will have the same value. This means that
-              you should have 191 different values of ic.
-                  %Solve for Currents: ia, ib, ic
-                 for m = 1:length(C)
-                 Impedances = [INSERT CODE HERE];
-                 A = [Vin;0;0];
-                 Currents = INSERT CODE HERE;
-                 ic(m) = Currents(3);
-                 end
-           c) Calculate Vout for every value of ic.
-           d) Calculate the phase shift of Vout in Reference to Vin.
-           e) Plot the phase shift as a function of capacitance
-           f) Question: Approximate the capacitor value that would create
-              a phase shift of 180 degrees.
-</file>
-== Image ==
-{{:240circuits:mt240_nr_9_9_1_mcmcomplex.png?300|}}
-== Template ==
-{{:240matlab:ch9:mt240_9_9_1_t_meshcurrentmethodtemplate.m|}}
-== Solution Image ==
-{{:240matlab:ch9:mt240_9_9_1_si_meshcurrentmethodsolutionimage.jpg?400|}}
 <ifauth @admin,@240ta>
 == Solution ==
+{{:240matlab:solutions:ch9:mt240_9_9_1_mesh_current_method.m|}}
+</ifauth>
-{{:240matlab:solutions:ch9:mt240_9_9_1_meshcurrentmethod.m|}}
+<ifauth @admin,@240ta>
-</ifauth>
 ===== Complex Power =====
@@ Line 355: / Line 282: @@
 {{:240matlab:ch10:mt240_10_4_1_si2_complexpowersolutionimage2.jpg?400|}}
-<ifauth @admin,@240ta>
 == Solution ==
@@ Line 361: / Line 288: @@
 </ifauth>
-===== Passive Filters =====
+===== Complex Power =====
-==== MT240.NR.14.4.1 ====
+==== MT240.NR.10.4.2 ====
+{{:240matlab:ch10:mt240_10_4_2_complex_power.pdf|}}
-<file>
-   MT240_14_4_1 Cross over network
-  Objective: Gain an understanding how you can use matlab to help you
+<ifauth @admin,@240ta>
-  design lowpass, bandpass, and highpass filters.
+== Solution ==
-  functions to learn: log10, semilogx
+{{:240matlab:solutions:ch10:mt240_10_4_2_complex_power.m|}}
+</ifauth>
-  Introduction: A crossover network consists of a highpass, lowpass, and
-  bandpass filter. They are often used in stereo systems that separates
-  a signal into three signals (bass, treble, and midrange). You will design
-  a basic crossover network as depicted in the image below.
-  Exercise: Design a crossover network with the following specifications:
+===== Passive Filters =====
-  |                        | Low pass | Bandpass | High pass |
+==== MT240.NR.14.4.1 ====
-  |Lower cut off frequency | N/A      |  250Hz   | 2000Hz    |
-  |Upper cut off frequency | 250Hz    |  2000Hz  | N/A       |
-  a) For each filter design you will be calculating the transfer function
-     of the voltage across each resistor. The equations should be simple
-     voltage division as shown in the book. See chapter 14. Design your
-     circuits choosing appropriate values for the capacitors and inductors.
-  b) Find the magnitudes (|H(jw)|) for v1, v2, and v3 as a function of 'w'
-    (frequency) with w being w = 0:10*2*pi:3e5*2*pi. Note that this is the
-     transfer function (H(jw) = vout/vin) thus the amplitude of the input voltage
-     source isn't needed in your calculations.
-) The midrange is a little more difficult so I provided you with the
-       steps.
-       a) Calculate the bandwidth. B = upper corner frequency - lower fc
-       b) Solve for the inductor using the relationship B = R/L
-       c) Solve for the capacitor value.
-  c) Plot the magnitude in decibels vs the frequency(Hz) using a
-     logarithmic scale. (use semilogx for this).
-  d) How could you design a bandreject filter that rejects frequencies
-     between 250Hz and 2000Hz?
-</file>
-== Image ==
-{{:240circuits:hw13.png?400|}}
+== Document ==
+{{:240matlab:ch14:mt240_14_4_1_crossover_network.pdf|}}
-== Template ==
-{{:240matlab:ch14:mt240_14_4_1_t_crossover_networktemplate.m|}}
-== Solution Image ==
-{{:240matlab:ch14:mt240_14_4_1_si_crossover_networksolutionimage.jpg?400|}}
 <ifauth @admin,@240ta>

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